12t^2-37t-10=0

Solution for 12t^2-37t-10=0 equation:

12t^2-37t-10=0

a = 12; b = -37; c = -10;
Δ = b2-4ac
Δ = -372-4·12·(-10)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-43}{2*12}=\frac{-6}{24}
=-1/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+43}{2*12}=\frac{80}{24}
=3+1/3
$